y=x^3lnx求dy/dx
1设y=x三次方lnx,求dy/dx 2 设 x=3t方 y=lnt,求dy/dx -
1 设y=x三次方lnx,求dy/dxy=x^3lnxdy/dx=d(x^2lnx)/dx=(2xlnx+x)2 设x=3t方 y=lnt, 求dy/dxdx/dt=(3t^2)'=6tdy/dt=(lnt)'=1/tdy/dx=(dy/dt)/(dx/dt)=(1/t)/(6t)=1/(6t^2)
1 设y=x三次方lnx,求dy/dxy=x^3lnxdy/dx=d(x^2lnx)/dx=(2xlnx+x)2 设x=3t方y=lnt, 求dy/dxdx/dt=(3t^2)'=6tdy/dt=(lnt)'=1/tdy/dx=(dy/dt)/(dx/dt)=(1/t)/(6t)=1/(6t^2)
1 设y=x三次方lnx,求dy/dxy=x^3lnxdy/dx=d(x^2lnx)/dx=(2xlnx+x)2 设x=3t方 y=lnt, 求dy/dxdx/dt=(3t^2)'=6tdy/dt=(lnt)'=1/tdy/dx=(dy/dt)/(dx/dt)=(1/t)/(6t)=1/(6t^2)
1 设y=x三次方lnx,求dy/dxy=x^3lnxdy/dx=d(x^2lnx)/dx=(2xlnx+x)2 设x=3t方y=lnt, 求dy/dxdx/dt=(3t^2)'=6tdy/dt=(lnt)'=1/tdy/dx=(dy/dt)/(dx/dt)=(1/t)/(6t)=1/(6t^2)
y=x^3lnx y'=3x^2lnx+x^3*(1/x)=3x^2lnx+x^2 所以:dy=x^2(3lnx+1)dx。
过程与结果如图所示,
Y=x^3lnx,求d^2/dx^2 -
dy/dx = 3x^2lnx + x^3*1/x = 3x^2 + x^2 d^2y/dx^2 = 6xlnx + 3x^2*1/x + 2x = 6xlnx + 5x
dy=(3x^2lnx+x^2)dx.
...1)已知y=x^3lnx,则y^n(1)= 2)设y=cos2x,则dy= 3)若y=2e^x+x^6...
1)已知y=x^3 lnx, y ' = 3x^2 lnx + x^2 y '' = 6x lnx + x, y ''' = 6 lnx + 1, y ''' = 6/x y ^ (n) = 6 * (-1)^(n-4) * (n-4)! / x^(n-3)y '(1) =1, y ''(1) =1, y '''(1) =1, y '''(1) = 6,y^(n) (1)有帮助请点赞。
y=3lnx,所以dy=(3/x)dx
设y=3inx,则dy=? -
解是y=3lnx吗y对x求导dy/dx=(3lnx)=3/x ∴ dy=(3/x)dx lnx的导数为:lnx)'=1/x
y=3lnx,所以dy=(3/x)dx
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y=x^3lnx求dy/dx